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Loci in Complex Plane

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发表于 20-1-2010 01:27 PM | 显示全部楼层 |阅读模式

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发表于 20-1-2010 01:59 PM | 显示全部楼层
For the first part, i think z is a circle with radius 1. We know that for z = R cos theta + i R sin theta, z2 = R2 cos 2theta + i R2 sin 2 theta. Therefore, we know that point Q is actually a bigger circle which has a radius of 3 unit and has a phase (theta) of twice of that of P. We know that the locus of Q has the same center as the locus of P which is at the origin. The minimum is when P and Q are in the same phase, to get that, we know that theta must be zero. It should turn out that the distance is 2 unit. On the other hand, the distance between P and Q should be maximum when the phases of P and Q are seperated by pi. To get that, you actually need your theta to be pi. Hence, i think you will get that the maximum distance between P and Q is 4.
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发表于 20-1-2010 02:09 PM | 显示全部楼层
For the second part, i think you just express z = Re + i Im, make the denominator real by multiplying both top and the bottom with the denometor's conjugate, and then take the i)length and ii)argument to compare with the right hand side (2 for part (i) and half pi for part (ii)). I think then you will get some function of Re in terms of Im. It will then be the locus you are looking for.
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发表于 21-1-2010 12:03 AM | 显示全部楼层
walrein_lim88, these questions are from further math past year paper, is it?
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 楼主| 发表于 21-1-2010 11:45 AM | 显示全部楼层
回复 4# 數學神童


    是的。。。。
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发表于 23-1-2010 08:46 PM | 显示全部楼层
神童,用华语。我英文不好。
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发表于 29-1-2010 01:23 PM | 显示全部楼层
请用中文发表, 谢谢.
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