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发表于 2-8-2010 09:42 PM
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回复 403# vick5821
I thought I have answered this question many times: Yes.  |
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发表于 2-8-2010 09:44 PM
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Ok..sorry to be so annoying..so actually in using the conservation of energy, PE lost = KE gained..so the KE is TOTAL KE?? if a sphere, so the total KE is combination of both but if for like box, the total KE = total KE is for translational only?? CORRECT?? |
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发表于 2-8-2010 09:46 PM
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回复 405# vick5821
Yes, you got it and I have wrote this at the very first sentence of my solution |
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发表于 2-8-2010 09:51 PM
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Ok..thanks..finally I learnt something .!! k..help me with the diagram one..thanks |
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发表于 2-8-2010 09:53 PM
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Hehe, as usual, I don't like to post my solution. I would like to know how are you analyzing the question. |
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发表于 2-8-2010 09:55 PM
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I dun even understand the ques..for this ques..u try to post some hints..but for just now that ques I really do not where I were wrong lor |
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发表于 2-8-2010 10:00 PM
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Hey, brb. Continue later. |
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发表于 2-8-2010 10:02 PM
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Ok..thanks very much!!!^^ |
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发表于 2-8-2010 10:47 PM
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回复 406# 数学系
oh ya..and based on what we calculated is for at the point when the ball reach the ground rite?? |
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发表于 3-8-2010 08:16 PM
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回复 381# vick5821
Help me with this..thanks |
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发表于 3-8-2010 10:24 PM
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发表于 3-8-2010 10:28 PM
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发表于 4-8-2010 08:29 PM
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thermodynamics of gases，有一种很唱出现的问题就是P against V 的 graph.
然后 gases undergo from A to B to C 然后return to original.
我想问在process当中number of moles of gases会不会变？
因为by applying PV=nRT at each point,the number of moles of gases 是不一样的？ |
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发表于 4-8-2010 08:41 PM
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[img] [/img] |
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发表于 5-8-2010 12:03 AM
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回复 345# whyyie
I dun understand ur working abt the total power!^&^ |
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发表于 5-8-2010 07:06 PM
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回复 whyyie
I dun understand ur working abt the total power!^&^
vick5821 发表于 5-8-2010 12:03 AM 
你楼上的那个问题有答案吗？ |
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发表于 5-8-2010 08:04 PM
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U mean the power de ques?? I got! |
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发表于 5-8-2010 08:14 PM
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U mean the power de ques?? I got!
vick5821 发表于 5-8-2010 08:04 PM
不是拉
是417楼的那个问题。。。 |
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发表于 6-8-2010 08:06 PM
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回复 417# vick5821
用principle of conservation of angular momentum,
L2=L1
I2w2=I1w1   , I=mr^2
w2m(r2)^2=w1m(r1)^2
w2=(r1/r2)^2 (10)     <----- v=rw1,5=0.5 X w1, w1=10
w2=(0.5/0.3)^2(10)
w2=27.77777778 rad s-1
v2=r2w2
v2=0.3(27.77777778)
v2=8.3333 ms-1 |
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发表于 6-8-2010 11:15 PM
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