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发表于 1-7-2007 02:31 AM
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this is the knowledge I learnt last year, I wonder if I can remember all of it, but i will try my best to explain it to you.
Photoelectric effect - Radiation can be regarded of comprising particles with energy - photons. When light is radiated towards the surface of a metal (or watever substances possible for photo effect), electrons of the metal atoms, if obtain sufficient energy from the photons, are able to escape from the metal atoms and become free electrons or photoelectrons.However, if the energy of the photon, which is related to the frequecy of the radiation ( E = hf ), is not high enough, no photoelectrons will be ever produced。Therefore, here comes the concept of work function, which can be defined as the minimum energy required to produce a photoelectron from a metal surface.In such a case, the values of work function different metal vary from one another.
Einstein equation is basically established based on the concept of the conservation of energy.
Energy of photon supplied=Work function+kinetic energy obtained by photoelectrons
or
hf = W + 1/2 mv^2
hf is the energy of the photon
W is the work funtion of the metal
1/2 mv^2 is the maximum kinetic energy otained by the photoelectrons
(its the maximum kinetic energy in the idealised case. But, in real life, some photoelectrons, upon liberated from metal surface, may lose some of its kinetic energy.)
This is the Einstein Equation for photoelectric effect.
We should note that if radiation with high intensity but with frequency lower than the threshold frequency of the related metal may NOT cause photoelectrics effect because each photon of the radiation possesses no energy (which only related to the frequency of the radiation)greater than the work function. Therehold frequency, fo, is the minimum frequency of the radiation required to produce photoelectric effect. Hence, work function, W = hfo。
Radiation with higher intensity indicates that there are more photons hit the suface of the metal per second. If the frquency of the radiation is able to produce photoelectrics effect, two radiation with that same frequency but different intensity, the one with higher intensity may produce more photoelectrons per second because there are more photons that land on the metal surface per second.
Hope that my explanation can help you a little bit more. |
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