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urgent 谁会,帮帮忙,我的脑转不过来
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1.express square root 44-24square root 2 in the form a+b square root 2 and state the value of a and b...
2.solve the eqution x^1/2+x^-1/2=2(x^1/2-x^-1/2)
3.given that p^1/2-p^-1/2=2,show that p+p^-1=6
4.given that 2^a=3^b=18^c,show that ab=c(b+2a)
plssssssssssssssssssssssssssssssss help me.....urgent |
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发表于 23-5-2010 06:08 PM
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1.express square root 44-24square root 2 in the form a+b square root 2 and state the value of a and b.
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发表于 23-5-2010 06:16 PM
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1.express square root 44-24square root 2 in the form a+b square root 2 and state the value of a and ...
非你不嫁 发表于 23-5-2010 05:16 PM 
44-24 Square root 2 = 20 Square root 2
如果我沒錯的話 |
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发表于 23-5-2010 06:29 PM
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2.solve the eqution x^1/2+x^-1/2=2(x^1/2-x^-1/2)
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发表于 23-5-2010 07:08 PM
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3.given that p^1/2-p^-1/2=2,show that p+p^-1=6
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发表于 23-5-2010 07:08 PM
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4.given that 2^a=3^b=18^c,show that ab=c(b+2a)
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发表于 23-5-2010 07:25 PM
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Q3) given that p^1/2-p^-1/2=2,show that p+p^-1=6
p^1/2-p^-1/2=2
p+1/p-2(p^1/2)[1/(p^1/2)]=4 (square both side)
p+1/p-2=4 (arrange)
p+1/p=6 (shown) |
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发表于 23-5-2010 07:30 PM
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Q3) given that p^1/2-p^-1/2=2,show that p+p^-1=6
p^1/2-p^-1/2=2
p+1/p-2(p^1/2)[1/(p^1/2)]=4 (squ ...
Lov瑜瑜4ever 发表于 23-5-2010 07:25 PM 
嗯,根据题目 Given ..., show that ...
的确应该这样解,干净利落,佩服..^^ |
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发表于 23-5-2010 07:33 PM
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Q2) solve the equation x^1/2+x^-1/2=2(x^1/2-x^-1/2)
x^1/2+x^-1/2=2(x^1/2-x^-1/2)
(x^1/2+x^-1/2)(x^1/2+x^-1/2)=2(x^1/2-x^-1/2)(x^1/2+x^-1/2) (both side multiple x^1/2+x^-1/2)
x+1/x+2=2(x-1/x)
x+1/x+2=2x-2/x
x-3/x-2=0
x^2-2x-3=0
(x-3)(x+1)=0
x=3 or x=-1
but only x=3 is accepted if x is an element of N
because x=-1 will make x^1/2 become complex number,i |
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发表于 23-5-2010 07:34 PM
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嗯,根据题目 Given ..., show that ...
的确应该这样解,干净利落,佩服..^^
乙劍真人 发表于 23-5-2010 07:30 PM 
多谢
彼此彼此切磋。。。 |
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发表于 23-5-2010 09:56 PM
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1.express square root 44-24square root 2 in the form a+b square root 2 and state the value of a and b...
这个我也有个方法...
[44-24(2^1/2)]^1/2
=(4^1/2)[11-6(2^1/2)]^1/2 (把4^1/2抽出来)
=2[11-2(18^1/2)]^1/2
=2[9-2(9x2)^1/2+2]^1/2
=2[3^2-2x3x(2^1/2)+(2^1/2)^2]^1/2 (弄成a^2-2ab+b^2的形式)
=2{[3-(2^1/2)]^2}^1/2 (a^2-2ab+b^2=(a-b)^2)
=2[3-(2^1/2)]
=6-2(2)^1/2
哈哈
我看到都有点乱
paiseh~ |
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楼主 |
发表于 24-5-2010 04:07 PM
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wa...
all expert
thx u all ya...^^ |
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