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发表于 15-2-2009 02:10 PM
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有学过substitution method 吗?
1) Let t^2 = 2x^2 - 2x + 1 ==> 2t dt = 4x - 2 dx
==> t dt = 2x - 1 dx
= Integrate [ -t/t dt] = Integrate - dt = -t + C = - sqrt[2x^2 - 2x + 1] + C
2) Let t^2 = tan x .....
3) 先用 sin 2x = 2 sin x cos x , 然后 let t = sin x ...
4) identity : 1/cos^2 x = sec^2 x .....
5) identity sin^2 x = (1 - cos 2x)/2 ....
6)identity cos^2 x = (1 + cos 2x)/2 ...
7) 先 expand 然后一个个 integrate
8) let t^2 = x ....
9) 用 2^(5x) = e^(5x*Ln 2) ,然后 用e 的integration |
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