C Programming : 怎样Pause Execution来看Output?

bryanliau91

如题.

我的Code:-

#include  

int main(int argc, char *argv[])
{ int i,j;
  int *p;

  if (argc > 1)
    i = atoi(argv[1]);
  else
  { fprintf(stderr, "usage: %s .\n", argv[0]);
    exit(1);
  
  }

  p = &i;
  j = *p + 2;

  *p = j / 2;

  printf("i = %d\n",i);
  printf("j = %d\n",j);
  printf("*p = %d\n",*p);


  
  exit(0);

}

麻烦了,抱歉.

Reader

put scanf(); before exist(0);

Reader

put scanf(); before exist(0);

bryanliau91

不能哦....................

Reader

不能哦....................
bryanliau91 发表于 4-11-2010 06:28 PM

put 1 more scanf in front of exit(1) also....please remember to set variable for scanf.
when the program run, it will stop at scanf and wait for your input. Before you input, the exit(0) and exit(1) will not run. so the program pause.

bryanliau91

回复 5# Reader
yes, before the input, i can see the execution.
but i want see the execution of output oo.

Reader

use break point lahh.....