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Newton Raphson
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1) Starting with x=3 as the first approximation, calculate by using Newton-Raphson method, a second approximation to 25^1/3, correct to four significant figures.
Answer: 2.926
From Ace Ahead textbook chapter Differentiation 7.13 question 5. |
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发表于 19-5-2010 09:52 PM
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1) Starting with x=3 as the first approximation, calculate by using Newton-Raphson method, a second ...
kelfaru 发表于 19-5-2010 09:41 PM 
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发表于 19-5-2010 09:55 PM
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walrein_lim88 发表于 19-5-2010 09:52 PM 
thanks a lot... |
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发表于 19-5-2010 10:01 PM
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walrein_lim88 发表于 19-5-2010 09:52 PM 
may i know why x=25^(1/3)? |
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发表于 19-5-2010 10:10 PM
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may i know why x=25^(1/3)?
kelfaru 发表于 19-5-2010 10:01 PM 
请用中文,谢谢
原因很简单:
现在你要找VALUE OF 25^(1/3)
所以:我们用UNKNOWN X ,LET X =25^(1/3) 把它FORM EQUATION来,就可以做了。。。然后找出VALUE OF X using newton raphson. |
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发表于 19-5-2010 11:09 PM
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回复 5# walrein_lim88
a second approximate to 25^(1/3)
这句话什么意思? |
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发表于 19-5-2010 11:21 PM
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回复 walrein_lim88
这句话什么意思?
peaceboy 发表于 19-5-2010 11:09 PM 
做两次的NEWTON RAPHSHON。。。 |
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发表于 19-5-2010 11:26 PM
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回复 7# walrein_lim88
意思是说第二次的F(x)=25^(1/3)?
我理解成second approximate = 25 ^(1/3)  |
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发表于 19-5-2010 11:30 PM
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回复 walrein_lim88
意思是说第二次的F(x)=25^(1/3)?
我理解成second approximate = 25 ^(1/3) ...
peaceboy 发表于 19-5-2010 11:26 PM 
对。。 |
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发表于 19-5-2010 11:50 PM
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回复 9# walrein_lim88
其实还是不太明白 25^(1/3)是什么意思.. |
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发表于 19-5-2010 11:54 PM
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回复 9# walrein_lim88
如果说第二次的F(x)= 25^(1/3),
拿到的formula = X^3 - 25
把3 sub进去后拿到 2,不是25^(1/3)为何? |
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