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急,帮我解决,谢谢!
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(1)solve the equation-4^(x)+5^(2x-1)=2^(2x+1)-25^x
(2) Express P(x)=x^4+3x^3+3x^2-x-6as a product of two linear factors and one quadratic factor.
(3) Obtain the first four terms in the expansion of (1-2x)^1/2 in ascending powers of x. by substituting 0.02 for x in(1-2x)^1/2 and its expansion, evaluate square root 6 correct to four decimal places.
(4) expand (1+2x) /(1-x)^4/3 in ascending powers of x,up to and including the fourth term.
(5) given that a^2,b^2 and c^2 are arithmetic progression,show that 1/(b+c),1/(c+a),1/(a+b) are also in arithmetic progression.
(6) find the sum of the first ten terms of the sequence
a+b , a^2+2b , a^3+3b , a^4+4b,….
蓝色是power
cheahengsoon@rocketmail.com
[ 本帖最后由 湘伦小雨 于 18-7-2009 08:58 PM 编辑 ] |
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发表于 18-7-2009 09:01 PM
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发表于 18-7-2009 09:07 PM
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发表于 18-7-2009 09:15 PM
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我不告诉你答案,因为我正在帮你
你考试时不可以用cari来问"答案"那该怎么办? |
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发表于 18-7-2009 10:55 PM
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发表于 19-7-2009 08:48 AM
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发表于 19-7-2009 10:01 AM
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-4^(x)-2^(2x+1)=-25^(x)-5^(2x-1)
2^(2x)+2^(2x+1)=5^(2x)+5^(2x-1)。。。。。。。。。。。。
太久没有做数学了 |
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发表于 19-7-2009 02:03 PM
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发表于 19-7-2009 03:18 PM
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发表于 20-7-2009 12:25 PM
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回复 1# 湘伦小雨 的帖子
自己做, 要不然你上課是來做什么的?  |
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发表于 21-7-2009 02:14 AM
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